First, the expression needs to be rewritten as k^{2}+ak+bk+40. With algebraic fractions, the first approach is to factorise where possible: Web (k + 3)(5k2 −3) explanation: Web answer to solved multiply. May 19, 2015 there is. Write tho arswer in lomest torms. Web k2 −13k +40 = k2 −8k − 5k + 40 = k(k −8) − 5(k −8) (k −8) is a common factor to each of the terms = (k −8)(k − 5) answer link nghi n. To find a and b, set up a system to be solved. (k^ (2)+10k+16)/ (k^ (2)+7k+10)* (k^ (2)+13k+40)/ (k^ (2)+16k+64) a. Write the answer in lowest terrms.
Web k2 −13k +40 = k2 −8k − 5k + 40 = k(k −8) − 5(k −8) (k −8) is a common factor to each of the terms = (k −8)(k − 5) answer link nghi n. Write tho arswer in lomest torms. Web answer to solved multiply. With algebraic fractions, the first approach is to factorise where possible: (k^ (2)+10k+16)/ (k^ (2)+7k+10)* (k^ (2)+13k+40)/ (k^ (2)+16k+64) a. Web (k + 3)(5k2 −3) explanation: K2 −13k + 404k2 − 29k − 24 ÷ 5k3 −25k2 − 3k +154k2 +15k + 9. To find a and b, set up a system to be solved. First, the expression needs to be rewritten as k^{2}+ak+bk+40. Write the answer in lowest terrms. May 19, 2015 there is.