SEM image of modified MnO2graphene nanosheets carbon electrode (inset
If 0.86 Mole Of Mno2. For hcl the coefficient is 4 so dividing 1.322/4=0.33. Which reagent will be used up first?
SEM image of modified MnO2graphene nanosheets carbon electrode (inset
So, one mole of kmno 4 oxidises 5 mole of ferrous ion. Web science chemistry q&a library mno2+ 4hcl →cl2+ mncl2+ 2h2o if 0.86 mole of mno2 and 48.2 g of hcl react, a. Web moles of mno2 = 0.86 moles the mole ratio between hcl:mno2 = 4:1. If 0.86 mole of mno2 and 48.2g of hcl react, which reagent will be used up first? Web correct option is a) the balanced chemical equation is as given below: Web ) = 0.86 mole m(hcl) = 48.2 g m(hcl) = 36.5 g/mole, m(cl 2) = 71 g/mole n(hcl) = m(hcl)/m(hcl) = 48.2/36.5 = 1.32 mole from the chemical equation: Web correct option is a) the balanced reaction is as follows: =3.44mol but hcl taken =1.32mol thus, hcl is the limiting reactant. Web o+cl 2 ? Which reagent will be used up first?
Web enter your answer in the provided box. Web science chemistry q&a library mno2+ 4hcl →cl2+ mncl2+ 2h2o if 0.86 mole of mno2 and 48.2 g of hcl react, a. If all 1.32 moles of hcl were used up then based on the mole ratio, the moles of mno2 that. Web enter your answer in the provided box. Web o+cl 2 ? Which reagent will be used up first? If 0.86 moles of mno2 and 48.2 grams of hcl react, which reagent will be. If 0.86 mole of mno2 and 48.2g of hcl react, which reagent will be used up first? Web correct option is a) the balanced reaction is as follows: Since 0.33 is less than 0.86 hcl is the limiting reagent. 1mol4mol 0.86mol 48.2g=1.32mol hcl required by 0.86 mol mno 2 ?
