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Now, \[\left( x + 2 \right)\] is a factor of p(x).p(x) = x 3 + x 2 + 4x + 12= (x + 2)(x. First, subtract (4x) and (10) from each side of the equation to put this equation into. Đặt t = x2 t = x 2 ( t ≥ 0 t ≥ 0 ). Web see a solution process below: X4 + 3x2 − 4 = 0 x 4 + 3 x 2 − 4 = 0. T2 + 3t− 4 = 0 t 2 + 3 t − 4 =. −x3 + 3x2 +2 = 0.
−x3 + 3x2 +2 = 0. Web see a solution process below: X4 + 3x2 − 4 = 0 x 4 + 3 x 2 − 4 = 0. −x3 + 3x2 +2 = 0. Now, \[\left( x + 2 \right)\] is a factor of p(x).p(x) = x 3 + x 2 + 4x + 12= (x + 2)(x. Đặt t = x2 t = x 2 ( t ≥ 0 t ≥ 0 ). First, subtract (4x) and (10) from each side of the equation to put this equation into. T2 + 3t− 4 = 0 t 2 + 3 t − 4 =.
