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2X 2 4X 3 0. The calculator solution will show work to solve a quadratic equation by completing the square to solve the entered equation for real and complex roots. A.2x2 + 4x + 7.
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Xem chi tiết lớp 8 toán câu hỏi của olm. 2x2 + 14x = 0 step. Step 1 :equation at the end of step 1 : To complete the square on l.h.s., we need last term = (m idl.t erm)2 4 ×f irstt erm = ( −4x)2 4 ⋅ 2x2 = 16x2 8x2 = 2 adding 2 on both sides, 2x2 − 4x +2 = 3 +2 ∴ 2(x2 −2x +1) = 5 ∴ 2(x − 1)2 = 5 ∴ (x −1)2 = 5 2 ∴ (x −1) = ± √ 5 2 ∴ x = 1 ± √ 5 2, is the desired soln. 2x2 + 4x = 3 2 x 2 + 4 x = 3 divide each term in 2x2 + 4x = 3 2 x 2 + 4 x = 3 by 2 2 and simplify. 2x2 + 4x = 0 step 2 : Step 1 :equation at the end of step 1 : X ≓ 2.269530773 x = 0 step by step solution : Step 1 :equation at the end of step 1 : 2x2 4x + 3 = 0 comparing equation with ax2 + bx + c = 0 a = 2, b = 4, c = 3 we know that d = b2 4ac d = ( 4)2 4 (2) (3) d = 16 24 d = 8 since d <<strong>0</strong> so, the given equation has no real roots.
Step 1 :equation at the end of step 1 : Step 3 :pulling out like terms : X ≓ 2.269530773 x = 0 step by step solution : Xem chi tiết lớp 8 toán câu hỏi của olm. 2x2 + 14x = 0 step. 2x2 4x + 3 = 0 comparing equation with ax2 + bx + c = 0 a = 2, b = 4, c = 3 we know that d = b2 4ac d = ( 4)2 4 (2) (3) d = 16 24 d = 8 since d <<strong>0</strong> so, the given equation has no real roots. ∴ 2x2 − 4x = 3. Xem chi tiết lớp 8 toán. Step 1 :equation at the end of step 1 : Step 1 :equation at the end of step 1 : Divide both sides of the equation by 2 to have 1 as the coefficient of the first term :
